950=-16t^2+1500

Solution for 950=-16t^2+1500 equation:

950=-16t^2+1500

We move all terms to the left:

950-(-16t^2+1500)=0

We get rid of parentheses

16t^2-1500+950=0

We add all the numbers together, and all the variables

16t^2-550=0

a = 16; b = 0; c = -550;
Δ = b2-4ac
Δ = 02-4·16·(-550)
Δ = 35200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{35200}=\sqrt{1600*22}=\sqrt{1600}*\sqrt{22}=40\sqrt{22}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{22}}{2*16}=\frac{0-40\sqrt{22}}{32}
=-\frac{40\sqrt{22}}{32}
=-\frac{5\sqrt{22}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{22}}{2*16}=\frac{0+40\sqrt{22}}{32}
=\frac{40\sqrt{22}}{32}
=\frac{5\sqrt{22}}{4}
$